Optimal. Leaf size=194 \[ \frac {e x^5 \left (d^2-e^2 x^2\right )^{p-2}}{2 p+1}-\frac {3 d \left (d^2-e^2 x^2\right )^p}{2 e^4 p}+\frac {2 d^5 \left (d^2-e^2 x^2\right )^{p-2}}{e^4 (2-p)}-\frac {2 e (3 p+4) x^5 \left (1-\frac {e^2 x^2}{d^2}\right )^{-p} \left (d^2-e^2 x^2\right )^p \, _2F_1\left (\frac {5}{2},3-p;\frac {7}{2};\frac {e^2 x^2}{d^2}\right )}{5 d^4 (2 p+1)}-\frac {7 d^3 \left (d^2-e^2 x^2\right )^{p-1}}{2 e^4 (1-p)} \]
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Rubi [A] time = 0.21, antiderivative size = 194, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.280, Rules used = {852, 1652, 446, 77, 459, 365, 364} \[ -\frac {2 e (3 p+4) x^5 \left (1-\frac {e^2 x^2}{d^2}\right )^{-p} \left (d^2-e^2 x^2\right )^p \, _2F_1\left (\frac {5}{2},3-p;\frac {7}{2};\frac {e^2 x^2}{d^2}\right )}{5 d^4 (2 p+1)}+\frac {e x^5 \left (d^2-e^2 x^2\right )^{p-2}}{2 p+1}+\frac {2 d^5 \left (d^2-e^2 x^2\right )^{p-2}}{e^4 (2-p)}-\frac {7 d^3 \left (d^2-e^2 x^2\right )^{p-1}}{2 e^4 (1-p)}-\frac {3 d \left (d^2-e^2 x^2\right )^p}{2 e^4 p} \]
Antiderivative was successfully verified.
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Rule 77
Rule 364
Rule 365
Rule 446
Rule 459
Rule 852
Rule 1652
Rubi steps
\begin {align*} \int \frac {x^3 \left (d^2-e^2 x^2\right )^p}{(d+e x)^3} \, dx &=\int x^3 (d-e x)^3 \left (d^2-e^2 x^2\right )^{-3+p} \, dx\\ &=\int x^3 \left (d^2-e^2 x^2\right )^{-3+p} \left (d^3+3 d e^2 x^2\right ) \, dx+\int x^4 \left (d^2-e^2 x^2\right )^{-3+p} \left (-3 d^2 e-e^3 x^2\right ) \, dx\\ &=\frac {e x^5 \left (d^2-e^2 x^2\right )^{-2+p}}{1+2 p}+\frac {1}{2} \operatorname {Subst}\left (\int x \left (d^2-e^2 x\right )^{-3+p} \left (d^3+3 d e^2 x\right ) \, dx,x,x^2\right )-\frac {\left (2 d^2 e (4+3 p)\right ) \int x^4 \left (d^2-e^2 x^2\right )^{-3+p} \, dx}{1+2 p}\\ &=\frac {e x^5 \left (d^2-e^2 x^2\right )^{-2+p}}{1+2 p}+\frac {1}{2} \operatorname {Subst}\left (\int \left (\frac {4 d^5 \left (d^2-e^2 x\right )^{-3+p}}{e^2}-\frac {7 d^3 \left (d^2-e^2 x\right )^{-2+p}}{e^2}+\frac {3 d \left (d^2-e^2 x\right )^{-1+p}}{e^2}\right ) \, dx,x,x^2\right )-\frac {\left (2 e (4+3 p) \left (d^2-e^2 x^2\right )^p \left (1-\frac {e^2 x^2}{d^2}\right )^{-p}\right ) \int x^4 \left (1-\frac {e^2 x^2}{d^2}\right )^{-3+p} \, dx}{d^4 (1+2 p)}\\ &=\frac {2 d^5 \left (d^2-e^2 x^2\right )^{-2+p}}{e^4 (2-p)}+\frac {e x^5 \left (d^2-e^2 x^2\right )^{-2+p}}{1+2 p}-\frac {7 d^3 \left (d^2-e^2 x^2\right )^{-1+p}}{2 e^4 (1-p)}-\frac {3 d \left (d^2-e^2 x^2\right )^p}{2 e^4 p}-\frac {2 e (4+3 p) x^5 \left (d^2-e^2 x^2\right )^p \left (1-\frac {e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (\frac {5}{2},3-p;\frac {7}{2};\frac {e^2 x^2}{d^2}\right )}{5 d^4 (1+2 p)}\\ \end {align*}
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Mathematica [A] time = 0.24, size = 202, normalized size = 1.04 \[ \frac {2^{p-3} \left (\frac {e x}{d}+1\right )^{-p} \left (d^2-e^2 x^2\right )^p \left (1-\frac {e^2 x^2}{d^2}\right )^{-p} \left (8 e (p+1) x \left (\frac {e x}{2 d}+\frac {1}{2}\right )^p \, _2F_1\left (\frac {1}{2},-p;\frac {3}{2};\frac {e^2 x^2}{d^2}\right )+(d-e x) \left (1-\frac {e^2 x^2}{d^2}\right )^p \left (12 \, _2F_1\left (1-p,p+1;p+2;\frac {d-e x}{2 d}\right )-6 \, _2F_1\left (2-p,p+1;p+2;\frac {d-e x}{2 d}\right )+\, _2F_1\left (3-p,p+1;p+2;\frac {d-e x}{2 d}\right )\right )\right )}{e^4 (p+1)} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.61, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{p} x^{3}}{e^{3} x^{3} + 3 \, d e^{2} x^{2} + 3 \, d^{2} e x + d^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{p} x^{3}}{{\left (e x + d\right )}^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.08, size = 0, normalized size = 0.00 \[ \int \frac {x^{3} \left (-e^{2} x^{2}+d^{2}\right )^{p}}{\left (e x +d \right )^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{p} x^{3}}{{\left (e x + d\right )}^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {x^3\,{\left (d^2-e^2\,x^2\right )}^p}{{\left (d+e\,x\right )}^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{3} \left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{p}}{\left (d + e x\right )^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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